Question on: JAMB Mathematics - 2007
A senatorial candidate had planned to visit seven cities prior to a primary election. However, he could only visit four of the cities. How many different itineraries could be considered?
A
640
B
840
C
520
D
920
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Correct Option: B
Number of itineraries = 7P4
=\(\frac{7!}{(7-4)!}\\ =\frac{7!}{3!}\\ =\frac{7 \times 6 \times 5 \times 4 \times 3!}{3!}\\ =840\)
=\(\frac{7!}{(7-4)!}\\ =\frac{7!}{3!}\\ =\frac{7 \times 6 \times 5 \times 4 \times 3!}{3!}\\ =840\)
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